I cant solve Cubic Minefeld. I dont know what i did wrong. Please

help.

Hi,

You want a function that is very similar to the one thatâ€™s above.

If we use the mult function, and try to find mult(4,5), then this calculates 4+4+4+4+4, which outputs 20.

We are trying to write the power function, so if we try to find power(4,5) then we want it to calculate 4x4x4x4x4 (which incidentally will output 1024).

The power function will be really similar to the mult function - what is the small change that you need to make?

Post again if you need more help.

Jenny

Well, thank you for helping, but I couldnt quite understand what you mean.

Ah OK. Do you know about powers? Ie what â€śtwo to the power of threeâ€ť means?

Jenny

To make things simple, you know what the Ă—(Multiplication) symbol does right? Itâ€™s basically adding the same number `n`

amount of times. ie 5 Ă— 7 can be expanded into:

5 + 5 + 5 + 5 + 5 + 5 + 5 = 35.

Now imagine powers as something like multiplication, except the + symbol is now Ă—. Hence 5 to the power of 7 would be something like:

5 Ă— 5 Ă— 5 Ă— 5 Ă— 5 Ă— 5 Ă— 5 = 78125.

In the function power, itâ€™s taking in two arguments, `number`

and `exponent`

. So if you were to write the function in pseudocode, it will be something like this:

- In variable
`total`

, for`exponent`

amount of times,`number`

will be multiplied by`number`

. - Return
`total`

.

If you wrote the function correctly, `hero.say(power(7,4))`

will make the hero. say `2401`

.