Mixed unit tactics pyhton

[Deadpool198]

@Shlomo

def commandTroops():
    friends = hero.findFriends()
    for friend in friends:  
        if friend.type != "palisade":
            for i in range(len(friends)):
                # Use % to wrap around defendPoints based on friendIndex
                # Command your minion to defend the defendPoint
                posi = defendPoints[i] % len(defendPoints)
                hero.command(friend, 'defend', defendPoints[posi])

This function has a few problems.
Firstly, why are you looping through your friends array twice? You do for friend in friends, then for i in range(len(friends)). You only want the for i in range(len(friends)). The first for loop is unnecessary.
Secondly, posi is incorrectly defined (this is actually very difficult, so I understand you having difficulty with it). At the moment, you are doing defendPoints[i] % len(defendPoints). Remember that defendPoints[i] is actually a coordinate, like {“x”: 44, “y”: 55}. You can’t use the % operator on it. Instead, you want to use i by itself, and divide that by len(defendPoints).
For more on % (modulo), you can read the post I wrote earlier, also about modulo, albeit in a different level:

How Does the Length of Built Objects % Summon Types Work?

So, first of all you have the array of types, which each have an index (from 0, to however many items you have in the array - 1, because it started at 0, not 1) e.g. summonTypes = ["archer", "soldier", "peasant", "paladin"] 0 1 2 3 So len(hero.built)%len(summonTypes) will always return a result within 0-3. We know that len(summonTypes) will always equal 4, because the number of items in the array won’t change in this level. So that side of the oper…

Danny