I will return to you later. Bye!
Andrei
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This post is supposed to stop the closure of this topic.
Andrei
2 Likes
Auto-closure fixed…for now.
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Thank you for your advice I will try it and see if it works.
1 Like
ok didn’t work new code though cause my bro made it and is trying to help me.
def add0s(on):
if len(on) < 8:
while len(on) < 8:
on = "0" + on
return on
def toTernary(number):
# Start with an empty string.
string = ""
# Then, while the number isn't zero:
while number != 0:
# We grab the remainder of our number.
remainder = number % 3
# This is our iterator method. 'number' decrements here.
number = (number - remainder) / 3
# Append the string to the remainder.
string = remainder + " " + string
# Finally we want to return our constructed string.
return string
def toBinary(number):
string = ""
# Go through the steps again:
# Get remainder, decrement, and append string.
# Remember that binary is another way of saying '2'!
while number != 0:
# We grab the remainder of our number.
remainder = number % 2
# This is our iterator method. 'number' decrements here.
number = (number - remainder) / 2
# Append the string to the remainder.
string = remainder + " " + string
# Finally we want to return our constructed string.
return string
while True:
friends = hero.findFriends()
for friend in friends:
if friend.type == "warlock":
des = friend.deployment
iss = toTernary(des)
for idd in iss:
if idd == "0":
hero.summon("soldier")
if idd == "1":
hero.summon("archer")
if idd == "2":
hero.summon("griffin-rider")
if friend.type == "paladin":
dep = friend.deployment
summ = toBinary(dep)
on = add0s(summ)
for od in on:
if od == "0":
hero.summon("soldier")
if od == "1":
hero.summon("archer")
for friend in friends:
xArr = [50, 45, 40, 35, 30, 25, 20, 15]
for x in xArr:
if friend.type != "warlock" and friend.type != "paladin":
hero.command(friend, "move", {'x': x, 'y': y})
I get an error saying that I need an object in line 11
does the add0s code look like it will work because it is not working for me
def add0s(summ):
if len(summ) < 8:
while len(summ) < 8:
summ = "0" + summ
pass
return summ
pass
else:
return summ
I haven’t extensively tested this but I think the problem with that function is that you’re trying to mix numbers and strings. You inputted a number and you’re trying to append a string onto it.
You’d have to do something like:
First you need two functions which aren’t used in CoCo: int() and str(). They turn whatever’s inside the brackets into either an integer or a string. (you cant turn text into an integer).
e.g.
string = '0'
integer = 999
sum = string + str(integer) # this will be '0999'. Remember it's a string!
# If you put int() before sum now, it will get rid of the 0 because 0999 isn't a proper number, but you want to keep it as a string.
I’m not exactly sure what you’re tactic is, but I hope this helps you work it out.
Danny
2 Likes
ok I figured it out some It was not running the if statement so I managed to get it to do that now I need it to actually add the 0s thanks for the help @Deadpool198 that was the problem. FYI I just needed to add this line:
summ = [summ]
to get the code to run.
1 Like
no I need to get the code to only add a 0 if it needs to
Ok, can you show us your new code?
Andrei
1 Like
def add0s(z):
if len(z) < 8:
while len(summ) < 8:
z = 0 + z
pass
return z
pass
else:
return z
pass
I meant can you show us your whole new code?
Andrei
1 Like
sorry I just finished it thanks for all yall’s help.
No problem! Anytime! And congratulations for completing the level! 
Andrei
1 Like