# [Solved] I need help with decoy drill

this is my code it should work

# Build 4 decoys, then report the total to Naria

decoysBuilt = 0
while True:
coin = hero.findNearestItem()
gold = hero.gold
if coin:
# Collect the coin!
hero.moveXY(coin.pos.x, coin.pos.y)

``````# Each decoy costs 25 gold.
# If hero.gold is greater than or equal to 25:
elif gold >= 25:
# buildXY a "decoy"
hero.buildXY("decoy", hero.pos.x, hero.pos.y)
# Add 1 to the decoysBuilt count.
decoysBuilt += 1
if decoysBuilt == 4:
# Break out of the loop when you have built 4.
break
pass
``````

hero.say(“Done building decoys!”)
hero.moveXY(14, 36)

# Say how many decoys you built.

hero.say(decoysBuilt)

Supposing your formatting is right ( correct your post ) you have this piece of code:

``````decoysBuilt = 0
while True:
coin = hero.findNearestItem()
gold = hero.gold
if coin:
hero.moveXY(coin.pos.x, coin.pos.y)
elif gold >= 25:
# some more code that will never execute if you have too many coins
``````

Change this elif to …
/ I really don’t like the structure of the default code:

``````    if condition1:
action1
if condition2:
action2
if condition3:
action3

``````

/

i figured it out solved