Toil and trouble! Please help

[Falcons118]

the for loop should be before this…

@QinWentian

if friend.type == "soldier":

[WaWa_Yang]

@QinWentian

if friend.type == “soldier”:

like @Falcons118 said, use a for loop. in your if loop check if there is a friend, and find its type.

[QinWentian]

Does not like it… Ducky says no

[WaWa_Yang]

can you send a screen shot

[WaWa_Yang]

wait nvm

@QinWentian

def chooseSoldierTarget():
    if friend.type == "soldier":
        enemies = hero.findEnemies()
        enemyIndex = 0
        while enemyIndex<len(enemies):
            enemy = enemies[enemyIndex]
            witch = hero.findNearest(hero.findByType("witch"))
            if enemy.type == witch:
                while enemy.health > 0:
                    hero.command(friend, "attack", enemy)
            enemyIndex+=1

make a variable for friends. Use a for loop, find if there is a friend and find its type.

@QinWentian

if enemy.type == witch:
                while enemy.health > 0:

use witch that you just defined

[Lydia_Song]

[SOLVED] Help! Toil and Trouble

Here’s something to get you started. This level only really takes 7 lines to beat it legitimately. But I don’t want to make things too confusing, so we’ll go with the long method. Step 1: Change the attackWitch function: Right now your attackWitch function doesn’t take any parameters, but here’s the catch – You can take an argument “friend”. So instead of having just def attackWitch(), you can do def attackWitch(friend). This will save you lines of code. Step 2: Edit the inside of the new at…

I think this post will help you out a lot.
Lydia