[SOLVED] Help! Rectangle Formation

[Lydia_Song]

"Code

# Form up soldiers and archers in rectangle formations.

# The distance between units.
step = 8

# First form up soldiers.
sergeant = hero.findNearest(hero.findByType("soldier"))
# The coordinates of the bottom left corner.
soldierX = 8
soldierY = 8
# The width and height of the formation.
width = sergeant.rectWidth
height = sergeant.rectHeight

for x in range(soldierX, soldierX + width + 1, 8):
    for y in range(soldierY, soldierY + height + 1, 8):
        hero.summon("soldier")
        lastUnit = hero.built[len(hero.built)-1]
        # Command the last built unit by using the  x/y variables:
        hero.command(lastUnit, "move", {'x': x, 'y':y})

# Next form up archers.
sniper = hero.findNearest(hero.findByType("archer"))
# The coordinates of the bottom left corner.
archerX1 = 48
archerY1 = 8
# The coordinates of the top right corner.
archerX2 = sniper.archerX2
archerY2 = sniper.archerY2

for x in range(archerX1, archerX2 + 1, 8):
    for y in range(archerY1, archerY2 + 1, 8):
        # Summon an archer.
        hero.summon("soldier")
        
        # Find the last built unit.
        lastUnit = hero.built[len(hero.built)-1]
        # Command the last built unit by using the  x/y variables:
        hero.command(lastUnit, "move", {'x':x, 'y':y})
        pass

Error

None but it ends up like this:

Link

https://codecombat.com/play/level/rectangle-formation?

Help appreciated!
Lydia

[Eric_Tang]

@Lydia_Song

for x in range(archerX1, archerX2 + 1, 8):
    for y in range(archerY1, archerY2 + 1, 8):
        # Summon an archer.
        hero.summon("soldier")

@Lydia_Song

hero.summon("soldier")
        

arent you suposed to summon archers

[Lydia_Song]

Ha! Silly me!
Lydia
20 chars

[Eric_Tang]

It happens to the best of us good job!