[QUOTE]
So, right “mythical phrase” is that:
             
            
              
            
           
          
            
            
              May you help me with my code?I can’t say the angle.
Find the vector of attack 
G=Vector(enemy.pos.x,enemy.pos.y)
Use trigonometry to find the the angle in Radians! 
A=Vector.subtract(hero.pos, enemy.pos)
The answer must be in Degrees! 
To convert Radians to Degrees multiply by (180 / Math.PI) 
degree=degree*180/Math.PI
Say the angle! 
hero.say(degree)
             
            
              
            
           
          
            
            
              I not use vectors, only function atan2.
    O=Math.abs(enemy.pos.y -self.pos.y) 
    A=Math.abs(enemy.pos.x-self.pos.x)
    angle=Math.atan2(O,A)
    angle=angle*180/Math.PI
    if enemy.pos.x<self.pos.x:
        angle=180-angle
    hero.say(angle) 
            
              
            
           
          
            
            
              I pass it. Thank you so much. But i still don’t understand it
             
            
              
            
           
          
            
            
              This is trigonometry. Learn it )))
             
            
              
            
           
          
            
            
              Yah. One moment. Function ATAN2 return value [-PI/2;PI/2], so if angle>90 degree, need calculate revers angle: 180-angle
             
            
              
            
           
          
            
            
              So angle=Math.atan2(O,A) means angle=O/A?
             
            
              
            
           
          
            
            
              yes. Only if angle <90 deg (or PI/2 in radians)
             
            
              
            
           
          
            
            
              so this is for negative angles?
             
            
              
            
           
          
            
            
              m? I dont know, what do you mean? If ogres are UNDER the hero?
             
            
              
            
           
          
            
            
              like enemy.pos.x<hero.pos.x,so A will negative. To prevent this, we have  if enemy.pos.x<self.pos.x:
             
            
              
            
           
          
            
            
              like enemy.pos.x<hero.pos.x
             
            
              
            
           
          
            
            
              like enemy.pos.x>hero.pos.x
             
            
              
            
           
          
            
            
              If ogr is to left from hero, then angle will >90 deg. Then:
Fuction atan2 return angle Ф (Theta). We need to calculate  (?). It  is equal to 180- atan2()
Understand?
             
            
              
            
           
          
            
              
                Serg  
              
                  
                    May 2, 2016,  5:23pm
                   
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              I double checked and fixed the ‘mythical’ phrase with the correct one:s(o/h), c(a/h), t(o/a).