Can someone help me to update this code in desert dual pls

AILeague
1 

hero.summon("big", 0)
hero.play("hot", 0)
hero.play("boost", 0)
hero.play("goliath", 0)

et1 = hero.findTheirPlayers(1)
et0 = hero.findTheirPlayers(0)
et2 = hero.findTheirPlayers(2)

def quicksand():
    et1 = hero.findTheirPlayers(1)
    et0 = hero.findTheirPlayers(0)
    et2 = hero.findTheirPlayers(2)
    if hero.isReady("quicksand"):
        if len(et1) >= 2: 
            hero.play("quicksand", 1) 
            if hero.isReady("press"): 
                hero.play("press", 2)
        elif len(et2) >= 2:
            hero.play("quicksand", 2) 
            if hero.isReady("press"): 
                hero.play("press", 1)
        elif len(et0) >= 2:
            hero.play("quicksand", 0)

while True:
    quicksand()
    if et0:
        hero.summon("big", 0) 
        hero.summon("threat", 0)  
        hero.summon("driver", 0)
        hero.play("hot", 0)
        hero.play("boost", 0)
    if et1:
        hero.summon("big", 1) 
        hero.summon("threat", 1)
        hero.summon("driver", 1)
        hero.play("boost", 1)
        hero.play("goliath", 1)
    if et2:
        hero.summon("big", 2)
        hero.summon("threat", 2) 
        hero.summon("big", 2)
        hero.play("goliath", 2)
        hero.play("boost", 2)
    if et0 and hero.isReady("hot") and hero.isReady("boost"):
        hero.summon("big", 0) 
        hero.play("hot", 0)
        hero.play("boost", 0)
    if et1 and hero.isReady("boost") and hero.isReady("goliath"):
        hero.summon("big", 1) 
        hero.play("boost", 1)
        hero.play("goliath", 1)
    if et2 and hero.isReady("goliath") and hero.isReady("boost"):
        hero.summon("big", 2) 
        hero.play("boost", 2)
        hero.play("goliath", 2)
    quicksand()
2

Hi @Xuan_Nguyen_Nguy_n! Welcome to the Discourse! :partying_face: This is a fun place to share your ideas, chat with some amazing people, and ask for help on CodeCombat levels. If you haven’t already, take a look at the new users’ guide. We hope you enjoy your time here! :tada:

Could you please format your code correctly to make it easier for us to help you?
Thanks,
Marmite

1 Like
3

here is my code if you want to look at it only 1 rules
1 do not copy it

my code. do not copy! 

# this fuction checks two lanes and sees which one has more enemys and plays quicksand
def findAndKill(target1,target2):
    if hero.isReady("quicksand"):
        if hero.findTheirPlayers(targerget2) > hero.findTheirPlayers(targerget1):
            hero.play("quicksand", target1)
        else:
            hero.play("quicksand", target2)
    pass
# this fuction sends troops to a specifid lane and bufs them up
def attack(target):
    hero.summon("big", target)   
    
    hero.summon("charger", target)
    hero.summon("driver", target)    
    hero.summon("sniper", target)
    hero.summon("threat", target)
    
    if hero.isReady("goliath"):
        hero.play("goliath", target)
    
    if hero.isReady("boost"):
        hero.play("boost",target )
    if hero.isReady("hot"):
        hero.play("hot",target )
    
pass
attack(1)
lastAttacket = 1
# this the main while true loop
while True:
    # this section checks how many enemys are in the top and bottom lanes and stores them in a variable
    e1 = hero.findTheirPlayers(1)
    
    e2 = hero.findTheirPlayers(2)
    
    # this if statment checks if e1 is less than e2 and runs the code inside
    if e1 < e2:
        # this variable stores which lane we are targeting
        attacking = 1
        
        # this checks if you last atacked the oposing lane and if so then it plays switch it also tells the code wether to run the findAndKill fuction
        if lastAttacket == 2 and hero.isReady("switch"):
            hero.play("switch")
            
            quicksand = 1
            
        else:
            quicksand = 0
            
        
        #this code checks if it should use the findAndKill fuction
        if quicksand == 1:
            
            findAndKill(0,2)
            
        
        attack(1)
        
        lastAttacket = 1
        
        thing = 2
        
    # this if statment is a mirror of the last code but for the oposing lane
    if e2 < e1:
        
        attacking = 2
        
        if lastAttacket == 1 and hero.isReady("switch"):
            
            hero.play("switch")
            
            quicksand = 1
            
        else:
            
            quicksand = 0
            
        if quicksand == 1 and hero.findTheirPlayers(1) > 0:
            
            findAndKill(0,1)
            
        attack(2)
        
        lastAttacket = 2
        
        thing = 1
        
    # this code is used in the event that both have the same amount of enemys
    if e2 == e1:
        attack(lastAttacket)
1 Like