For the level Hunters and Prey in Cloudrip Mountain the sample code is in Javascript while I use Python. When I put a python code my whole code ends up being wrong. Does anyone have any solutions???
press reload on the top right corner
I already tried but it still ends up in Javascript.
did go to hero and check if its python
I did and it shows that I am using python. This is my code:
# Ogres are trying to kill your reindeer!
# Keep your archers back while summoning soldiers to attack.
def pickUpCoin():
coin = self.findNearest(self.findItems())
if coin:
self.move(coin.pos)
pass
def summonTroops():
if self.gold > self.costOf("soldier"):
self.summon("soldier")
# Summon soldiers if you have the gold.
pass
# This function has an argument named soldier.
# Arguments are like variables.
# The value of an argument is determined when the function is called.
def commandSoldier(soldier):
enemy = soldier.findNearestEnemy
if enemy:
self.command(soldier, "attack", enemy)
# Soldiers should attack enemies.
pass
# Write a commandArcher function to tell your archers what to do!
# It should take one argument that will represent the archer passed to the function when it's called.
# Archers should only attack enemies who are closer than 25 meters, otherwise, stay still.
def commandarcher(archer):
enemy = archer.findNearest(archer.findenemies)
if enemy and archer.distanceTo(enemy) < 25:
self.command(archer, "attack", enemy)
else:
self.command(archer, "move", archer.pos)
loop:
pickUpCoin()
summonTroops()
friends = self.findFriends()
for friend in friends:
if friend.type == "soldier":
# This friend will be assigned to the variable soldier in commandSoldier
commandSoldier(friend)
elif friend.type == "archer":
commandarcher(friend)
mabye you should ask nick if you think this is a glitch
I have invited him and am waiting for him to come.
so you did @ and then nick
@nick Please help me Out!!!
What’s your CodeCombat username? I’ll check it out. It sounds like if you go to the hero selection screen and pick both a different hero and a different programming language, you might be able to switch it back to Python.
It is DarkShadow66!!!
If nothing works @nick can someone just translate this to Javascript and give me the translated code!Thx
My code:
loop:
coin = self.findNearest(self.findItems())
enemy = self.findNearest(self.findEnemies())
friends = self.findFriends()
if coin:
self.move(coin.pos)
if self.gold >=20:
self.summon("soldier")
for friend in friends:
if friend.type is "soldier":
self.command(friend, "move", {'x':25, 'y':70})
elif enemy:
if friends:
for friend in friends:
if friend.type is "soldier":
self.command(friend, "attack", enemy)
for friend in friends:
if friend.type is "archer":
self.command(friend, "move", {'x':25, 'y':25})
elif enemy:
if friends:
for friend in friends:
if friend.type is "archer":
self.command(friend, "attack", enemy)
I need a answer in at least 2 days because I am falling behind everyone in my class!
wait i thought you just said you were using python
try exploiting it for now i found a exploit by accident and the ogre attacked the soldiers instead
so i built summoned archers around the deers and the ogres did not spawn around them because they cant spawn near archer (summon not build and dont command)
All I need is someone to translate my code to JavaScript
How to translate the code into javascript:
- put “;” after each instruction. If you forget, the compiler will tell you to do it EASY.
- put a “var” to declare the variable each time you write a new variable. If you put too many var or not enough the compiler will tell you EASY
friends = self.findFriends()
becomes:
var friends = self.findFriends();
- Put the if or for in the parentheses
- Remove the “:” after if or for
- Put brackets “{” around the instructions inside the if or for
DIFFICULTY: STRAIGHT FORWARD
if friends:
for friend in friends:
if friend.type is "soldier":
self.command(friend, "attack", enemy)
becomes
if (friends){
for (friend in friends){
if (friend.type is "soldier"){
self.command(friend, "attack", enemy);
}
}
}
- Inside the “if” argument python uses “is” for equal, “not” for negation,
“is not” for not equal. Javascript uses “==”, “!” and "!="
DIFFICULTY: EASY
Python JavaScript
is ==
not !
is not !=
so
if friend.type is "archer":
becomes:
if (friend.type == "archer"){
- In JavaScript the for in works different: it will give you the index of
an element instead of the object element.
You need to add this line immediately after the for:
friend=friends[i];
DIFFICULTY: YOU"LL FIGURE IT OUT
for friend in friends:
if friend.type is "archer":
self.command(friend, "attack", enemy)
becomes:
for (i in friends){
friend=friends[i];
if (friend.type == "archer"){
self.command(friend, "attack", enemy);
}
}
- Replace all self with this
self.command(friend, "attack", enemy)
becomes
this.command(friend, "attack", enemy);
Congratulations, you have now learned how to program in JavaScript !!
- Learn to program in both Python and Javascript, ask your schoolmates for help. Do not rely on code copied from internet.
DIFFICULTY: HARD BUT WORTH IT.
1 Like
You know what my mind is getting messed up because I have many problems going on. So can someone just send me the translated code in my gmail!!Thx
PLEASE PLEASE PLEASE PLEASE
My gmail:
crummyface126@gmail.com