Hello cool peeps!
In this mission you are meant to use 4 variables to answer a wizards riddles. (Green circle)
The comment over the last section instructs that one should use all five variable. (Red circle)
I succeded with using the four i found in the code.
Can someone tell me if this is meant to be written as is? Maybe i am not reading it right or it might be a typo?
You can go onto the level editor:
I had no idea. So cool…!
Thank you :).
But wait… Can anyone do that?
Yes, but it doesn’t get put into effect in the real level until someone (an admin) confirms it.
Danny
I did it, i think!
I am a kluts though! I hit enter to early when i was commenting on my changes… xD LE SIGH!!
Super cool to be able to look under the hood. Thanks so much DeadPool! 
There are 5 variables:
a; b; c;
d = a && b && c;
f = a || b || c;
and the last check is designed to be ( a && b && c && d && f)
but…
if (a && b && c ) is true ( a || b || c) is also true:
so the last check can be only ( a && b && c )
I think the text and the default solution are a little bit misleading but not wrong…
Congratulations for being for a while under the hood!
(replace auto with var - how do you think - will be there an error? -
Hello xython :).
Ah! I thought there might be meaning in the madness!
Thank you for replying.
A good thing it is that not any madman can go change the source files xD…
I think you are right in your thoughts about misleading comments. And maybe that is how it is supposed to be :).
var is an Interesting type definition. It is not anything i have been taught about yet. Cool! 
It is always nice to learn about new stuff… Im gonna look it up now.
Thank you! It was overwhelming and very confusing. But super cool! I did not find the CPP files. Are they not accessible?
